Calendar issues | Find any day without giving data

 

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Solve calendar days in less than a minute

When solving calendar issues you should start noting according to the instructions in the problem. It helps in solving problems. Every problem challenges thinking ability, direction of thinking, speed, memory. On a particular date, the day of the week is given and you are asked to find the day on another date. These types of questions can also be asked in interviews. I would like to draw your attention to the following points:

  1. 28, 29, 30, or 31 in special months.
  2. Total weeks in the year = 52 weeks.
  3. The cycle of days repeats after every 7th day.
  4. There are 365 days in an ordinary year, 366 days in a leap year (completely divisible by 4).
  5. If January 1 is Friday, December 31 will be the same day.

Method to solve calendar issues

Examples: If it was a Monday on the first day of the year 1996. What day was 8 January 1998?

Solution: The year 1996 is a leap year in the calendar. There are 366 days in a year. If the remainder is divisible by 7. 2. Hanes, on 1 January 1997, the day will be Wednesday. On 1 January 1998, the day will be Thursday. Therefore, on 8 January 1998, the day will be Thursday (1 + 7).

Search any day The data

Examples: What a day on 12 August 2000.

Solution: August code = 2, date = 12, year code = 6, 2000 is a leap year because it is completely divisible by 4. Now 12 (date) +2 (month code) +6 (year code) +0 (2000+) 0 ient) + 0 (quotient of 0/4) = 20. So divide the total by 7, the remainder is 6 and Saturday is the 6th day. So 12 August 2000 will be the day Saturday.

January February March April May June July August September October November December
0 3 3 6 1 4 6 2 5 0 3 5
Code for the month
Monday Tuesday Wednesday Thursday Friday Saturday Sunday
1 2 3 4 5 6 0
Code for days
6 4 2 0
1600 (year) 1700 1800 1900
2000 2100 2200 2300
Code for the year

Try yourself for more practice: https://cracku.in/blog/ssc-questions-on-calendar-pdf/

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